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15 <H1>[IRCServices Coding] Introduced module's Psuedoclient is invalid
16 user.</H1>
17 <B>Olly</B>
18 <A HREF="mailto:ircservices-coding%40ircservices.esper.net?Subject=%5BIRCServices%20Coding%5D%20Introduced%20module%27s%20Psuedoclient%20is%20invalid%0A%09user.&In-Reply-To=43008d47.75063%40msgid.achurch.org"
19 TITLE="[IRCServices Coding] Introduced module's Psuedoclient is invalid
20 user.">olly at avansys.co.uk
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22 <I>Mon Aug 15 10:06:23 PDT 2005</I>
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39 <PRE>This is crazy. For some reason I can't seem to get a valid channelinfo
40 struct from the check_kick call-back, so I can't tell which channel is
41 being joined. Is this a bug, or am I missing something?
42
43 Olly
44
45 -----Original Message-----
46 From: <A HREF="http://lists.ircservices.za.net/mailman/listinfo/ircservices-coding">ircservices-coding-bounces at ircservices.esper.net</A>
47 [mailto:<A HREF="http://lists.ircservices.za.net/mailman/listinfo/ircservices-coding">ircservices-coding-bounces at ircservices.esper.net</A>]On Behalf Of
48 Andrew Church
49 Sent: 15 August 2005 22:39
50 To: <A HREF="http://lists.ircservices.za.net/mailman/listinfo/ircservices-coding">ircservices-coding at ircservices.esper.net</A>
51 Subject: RE: [IRCServices Coding] Introduced module's Psuedoclient is
52 invalid user.
53
54
55 Looks like our messages crossed paths, but--
56
57 &gt;<i>Okay here's a couple of questions..
58 </I>&gt;<i>Can I force Services to produce a valid user struct for the
59 </I>&gt;<i>psuedoclient?
60 </I>
61 No, as per my previous mail.
62
63 &gt;<i>Can I find out if a channel join from any user is the first time that
64 </I>an
65 &gt;<i>empty channel has been joined?
66 </I>
67 See the autokick code in modules/chanserv/check.c:check_kick(),
68 which
69 includes code (and comments) to check whether a user is the only user in
70 the channel both at and after join time.
71
72 --Andrew Church
73 <A HREF="http://lists.ircservices.za.net/mailman/listinfo/ircservices-coding">achurch at achurch.org</A>
74 <A HREF="http://achurch.org/">http://achurch.org/</A>
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